如何从字符串列表中的每个字符串中删除最后一个字符 [英] How to delete the very last character from every string in a list of strings

问题描述

我在列表中有字符串"80010"，"80030"，"80050"，如

I have the strings '80010', '80030', '80050' in a list, as in

test = ['80010','80030','80050']

如何删除最后一个字符(在这种情况下，每个字符串的最后一个数字为0)，这样我才能得到另一个仅包含每个字符串的前四位数字/字符的列表.所以最后得到

How can I delete the very last character (in this case the very last digit of each string which is a 0), so that I can end up with another list containing only the first four digits/characters from each string? So end up with something like

newtest = ['8001', '8003', '8005']

我对Python非常陌生，但是我尝试使用if-else语句，追加，使用索引[:-1]等，但是除非最终删除所有其他零，否则似乎没有任何效果.非常感谢！

I am very new to Python but I have tried with if-else statements, appending, using indexing [:-1], etc. but nothing seems to work unless I end up deleting all my other zeros. Thank you so much!

推荐答案

test = ["80010","80030","80050"]
newtest = [x[:-1] for x in test]

新测试将包含结果["8001","8003","8005"].

[x[:-1] for x in test]通过遍历test中的每个项目并将修改后的版本放入newtest中来创建新列表(使用 list理解). x[:-1]表示将字符串值x中的所有内容取为最大值，但不包括最后一个元素.

[x[:-1] for x in test] creates a new list (using list comprehension) by looping over each item in test and putting a modified version into newtest. The x[:-1] means to take everything in the string value x up to but not including the last element.

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