在Python字典中获取键/值对的所有组合 [英] Getting all combinations of key/value pairs in Python dict

问题描述

这可能是一个愚蠢的问题，但要注意以下几点:

This may be a silly question, but given the following dict:

combination_dict = {"one": [1, 2, 3], "two": [2, 3, 4], "three": [3, 4, 5]}

我将如何获得此列表:

result_list = [{"one": [1, 2, 3], "two": [2, 3, 4]}, {"one": [1, 2, 3], "three": [3, 4, 5]}, {"two": [2, 3, 4], "three": [3, 4, 5]}]

换句话说，我希望字典中两个键/值对的所有组合都不能替换，而与顺序无关.

In other words, I want all combinations of two key/value pairs in a dict without replacement, irrespective of order.

推荐答案

一种解决方案是使用itertools.combinations():

result_list = map(dict, itertools.combinations(
    combination_dict.iteritems(), 2))

编辑:由于

Edit: Due to popular demand, here a Python 3.x version:

result_list = list(map(dict, itertools.combinations(
    combination_dict.items(), 2)))

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