如何从列表字典的值中获取所有键? [英] How to get all keys from a value for a dict of lists?

问题描述

我有这样格式的字典

d = {
    "Fruit_1" : ["mango", "apple"],
    "Fruit_2" : ["apple"],
    "Fruit_3" : ["mango", "banana", "apple", "kiwi", "orange"]
}

我传递的值是"mango"，我想获得所有仅芒果出现的对应键.我无法在出现值的任何地方获取相应的键.

I'm passing a value as "mango" and I want to get all corresponding keys where only mango occurs. I am not able to get corresponding keys where ever value occurs.

推荐答案

您也许可以这样做:

d = {
    "Fruit_1" : ["mango", "apple"],
    "Fruit_2" : ["apple"],
    "Fruit_3" : ["mango", "banana", "apple", "kiwi", "orange"]
}

# list comprehension
mango_keys = [fruit for fruit in d.keys() if "mango" in d[fruit]]
print(mango_keys)       


# ['Fruit_1', 'Fruit_3']         


# or more traditional for-loop (but non pythonic)

for fruit in d.keys():
    if "mango" in d[fruit]:
        print(fruit)

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