在Python中，如何在保持单词顺序的同时从两个列表中查找常用单词? [英] In Python, how do I find common words from two lists while preserving word order?

问题描述

我正在尝试找到一种简单的方法来做到这一点:

I am trying to find an easy way to do this:

list1 = ['little','blue','widget']
list2 = ['there','is','a','little','blue','cup','on','the','table']

我想获得两个列表的共同元素，而list1的顺序保持不变，因此可以预期此结果.

I want to get common elements of the two lists, with list1's order untouched, so this result is expected.

list3 = ['little','blue']

我正在使用

list3 = list(set(list1)&set(list2))

但是，这只会返回list3 = ['blue'，'little']，显然，set()只是忽略了顺序.

however, this only returns list3 = ['blue', 'little'], obviously, set() just ignore the order.

任何帮助将不胜感激！

推荐答案

您快到了，只需根据list1

list1 = ['little','blue','widget']
list2 = ['there','is','a','little','blue','cup','on','the','table']

list3 = set(list1)&set(list2) # we don't need to list3 to actually be a list

list4 = sorted(list3, key = lambda k : list1.index(k))

结果:

>>> list4
['little', 'blue']

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