numpy-等效于list.pop? [英] numpy-equivalent of list.pop?

问题描述

是否有一个numpy方法与python列表的内置pop等效?

Is there a numpy method which is equivalent to the builtin pop for python lists?

在numpy数组上显然无法进行抽奖，并且我想避免列表转换.

Popping obviously doesn't work on numpy arrays, and I want to avoid a list conversion.

推荐答案

NumPy数组没有pop方法，但是您可以只使用基本切片(这很有效，因为它返回一个视图，而不是副本) :

There is no pop method for NumPy arrays, but you could just use basic slicing (which would be efficient since it returns a view, not a copy):

In [104]: y = np.arange(5); y
Out[105]: array([0, 1, 2, 3, 4])

In [106]: last, y = y[-1], y[:-1]

In [107]: last, y
Out[107]: (4, array([0, 1, 2, 3]))

如果有pop方法，它将在y中返回last值并修改y.

If there were a pop method it would return the last value in y and modify y.

以上

last, y = y[-1], y[:-1]

将最后一个值分配给变量last并修改y.

assigns the last value to the variable last and modifies y.

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