从JSON对象中提取2个值，并使用jq和bash在循环中用作变量 [英] extract 2 values from JSON object and use as variables in loop using jq and bash

问题描述

我是jq的新手.我正在尝试编写一个简单的脚本，该脚本遍历JSON文件，在每个对象中获取两个值，并将它们分配给两个单独的变量，我可以在curl REST调用中使用它们.当我回显$ i时，我将两个值都视为输出，但是如何将值和addr作为单独的变量获取呢?

I am new to jq. I am trying to write a simple script that loops through a JSON file, gets two values within each object and assigns them to two separate variables I can use with a curl REST call. I see both values as output when I echo $i but how can I get value and addr as separate variables?

for i in `cat /Users/egraham/Downloads/test2  | jq .[] | jq ."value,.addr"`; do

推荐答案

如果空格或制表符或其他特殊字符使使用'read -r'产生问题，并且如果您的外壳具有"readarray"，则可以使用: /p>

If spaces or tabs or other special characters make using 'read -r' problematic, and if your shell has "readarray", then it could be used:

$ readarray -t v < <(jq -rc '.populator | (.value,.addr)' file.json)

这些值将分别作为$ {v [0]}和$ {v [1]}

The values would then be available as ${v[0]} and ${v[1]}

如果感兴趣的值多于两个，或者值的数量是可变的或事先未知，则此方法特别有用.

This approach is especially useful if there are more than two values of interest, or if the number of values is variable or not known beforehand.

如果您的shell没有readarray，那么您仍然可以使用面向数组的方法，例如遵循以下原则:

If your shell does not have readarray, then you can still use the array-oriented approach, e.g. along the lines of:

i=-1; while read -r a ; do i=$((i+1)); v[$i]="$a" ; done

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