C ++ Mac OS X regex(“.*")与regex_replace()导致无限循环 [英] c++ mac os x regex(".*") causes infinite loop with regex_replace()
问题描述
这会导致无限循环:
std::regex_replace("the string", std::regex(".*"), "whatevs");
这不会导致无限循环:
std::regex_replace("the string", std::regex("^.*$"), "whatevs");
Mac regex实施有什么问题?使用Mac OS X El Capitan Xcode 7.1
What is wrong with Mac regex implementation? using Mac OS X El Capitan Xcode 7.1
this question is related to: C++ Mac OS infinite loop in regex_replace if given blank regex expression
推荐答案
.*
首先匹配整个字符串,然后匹配空字符串,因为*
表示"匹配0个或更多匹配项"前面的子模式".空字符串匹配可能是无限循环的原因,但是我不确定这是错误还是设计错误.
The .*
matches the whole string first, and then the empty string at the end because *
means "match 0 or more occurrences of the preceding subpattern". The empty string match is probably the cause of the infinite loop, but I'm not sure whether it's a bug or by-design.
您可以使用std::regex_constants::match_not_null
覆盖行为(请参见 regex_replace
c ++参考 ):
You can override the behavior using std::regex_constants::match_not_null
(see regex_replace
c++ reference):
match_not_null
不为空空序列不匹配.
C ++代码演示仅返回whatevs
:
std::regex reg(".*");
std::string s = "the string";
std::cout << std::regex_replace(s, reg, "whatevs",
std::regex_constants::match_not_null) << std::endl;
请注意,您观察到的无限循环"很可能是一个错误,因为源代码暗示一旦将空字符串传递给regex引擎,就应该引发异常.它尚未记录在任何地方.我认为(不确定)问题可能出在为替换操作收集匹配项时regex_replace
方法如何处理字符串.
Note that the "infinite loop" you observe is most likely a bug since the source code hints that an exception should be thrown once an empty string is passed to the regex engine. It is not yet logged anywhere. I think (not sure) the issue might be with how the string is handled by the regex_replace
method when matches are collected for a replace operation.
发生了什么事:regex_replace
调用
basic_string<_Elem, _Traits1, _Alloc1> regex_replace(const basic_string<_Elem, _Traits1, _Alloc1>& _Str, const basic_regex<_Elem, _RxTraits>& _Re, const _Elem *_Ptr, regex_constants::match_flag_type _Flgs = regex_constants::match_default)
{ // search and replace, string result, string target, NTBS format
basic_string<_Elem, _Traits1, _Alloc1> _Res;
const basic_string<_Elem> _Fmt(_Ptr);
regex_replace(_STD back_inserter(_Res), _Str.begin(), _Str.end(),
_Re, _Fmt, _Flgs);
return (_Res);
}
_Res
是一个空字符串,_Fmt
现在是 whatevs .然后,调用regex_replace
. _Str.end()
等于10
,并初始化了一个指针.
_Res
is an empty string, _Fmt
is now whatevs. Then, the regex_replace
is called. _Str.end()
equals 10
, and a pointer is initialized.
_First
等于字符串,而_Last
等于空字符串.
_First
equals the string and _Last
equals an empty string.
它是内部char缓冲区处理的结果,其指针实际上包含以下数组:
It happens as a result of internal char buffer processing whose pointer actually contains an array of:
inline back_insert_iterator<_Container> back_inserter(_Container& _Cont)
方法首先从前0到9个字符中创建一个字符串,然后从10到15个数组元素(以空终止符开头的一个)中创建一个字符串.
The inline back_insert_iterator<_Container> back_inserter(_Container& _Cont)
method first creates a string out of the first 0 to 9 chars, and then from 10 to 15 array elements (the one starting with the null terminator).
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