按值对嵌套字典进行排序 [英] Sort nested dictionary by values

问题描述

我正在尝试对其中的另一本词典进行排序.这是我的字典的样子:

I am trying to sort a dictionary with another dictionary inside. This is how my dict looks like:

{'POS2': {'stegano': 0, 'sum': 200, 'misc': 100, 'web': 0, 'ppc': 0, 'crypto': 0, 'admin': 0, 'vuln': 0, 'forensics': 0, 'hardware': 0, 'reverse': 0, 'recon': 100}, ...}

我想通过存储在嵌套字典中的'sum'键对其进行排序.我尝试了其他解决方案，例如排序在Python中和此处

I want to sort it by 'sum' key that is stored in nested dict. I have tried different solutions like here Sort nested dictionary by value, and remainder by another value, in Python and here sorting a nested dictionary with lists in python but they all work fine on python 2.x but doesn't work on python 3.x. Could you give me advice how to implement this kind of sort ?

推荐答案

从每个项目简单地返回所需的排序键

Simply return the desired sort key from each item

sorted(inputdict.items(), key=lambda item: item[1]['sum'])

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