如何按字典值对字典列表进行排序? [英] How do I sort a list of dictionaries by a value of the dictionary?

问题描述

我有一个词典列表，希望每个项目都按特定的属性值排序.

I have a list of dictionaries and want each item to be sorted by a specific property values.

考虑下面的数组，

[{'name':'Homer', 'age':39}, {'name':'Bart', 'age':10}]

按name排序时，应变为

[{'name':'Bart', 'age':10}, {'name':'Homer', 'age':39}]

推荐答案

使用键而不是cmp看起来更干净:

It may look cleaner using a key instead a cmp:

newlist = sorted(list_to_be_sorted, key=lambda k: k['name']) 

或正如塞巴斯蒂安·J·F·塞巴斯蒂安(J.F. Sebastian)等建议的那样，

or as J.F.Sebastian and others suggested,

from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name')) 

为完整起见(如fitzgeraldsteele的评论所指出)，请添加reverse=True以降序排列

For completeness (as pointed out in comments by fitzgeraldsteele), add reverse=True to sort descending

newlist = sorted(l, key=itemgetter('name'), reverse=True)

这篇关于如何按字典值对字典列表进行排序?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！