按字典键的整数对字典进行排序 [英] Sort dictionary by integers of dictionary keys

问题描述

假设我有这样的字典:

thedict={'1':'the','2':2,'3':'five','10':'orange'}

，我想按键对这本字典进行排序.如果我执行以下操作:

and I want to sort this dictionary by key. If I do the following:

for key,value in sorted(thedict.iteritems()):
     print key,value

我会得到

1 the
10 orange
2 2
3 five

因为键是字符串而不是整数.我想对它们进行排序，就好像它们是整数一样，因此条目"10，orange"排在最后.我以为这样的事情会起作用:

since the keys are strings and not integers. I want to sort them as if they are integers, so the entry "10,orange" comes last. I thought something like this would work:

for key,value in sorted(thedict.iteritems(),key=int(operator.itemgetter(0))):
    print key,value

但是会产生此错误:

TypeError: int() argument must be a string or a number, not 'operator.itemgetter'

我在这里做错了什么?谢谢！

What am I doing wrong here? Thanks!

推荐答案

我认为您可以使用lambda表达式来做到这一点:

I think you could do that easy enough with a lambda expression:

sorted(thedict.iteritems(), key=lambda x: int(x[0]))
# with Python3, use thedict.items() for an iterator

问题是您将可调用对象传递给内置的int()，并试图将int()调用的返回值用作键的可调用对象.您需要为key参数创建一个callable.

The problem is that you are handing a callable object to the int() builtin and trying to use the return value of the int() call as a callable for the key. You need to create a callable for the key argument.

您得到的错误基本上告诉您，您不能使用操作符来调用int().itemgetter(可调用)只能使用字符串或数字来调用.

The error you are getting basically tells you that you can't call int() with an operator.itemgetter (callable), you can only call it with a string or a number.

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