如何创建包含文本文件中的键值对的字典 [英] How to create a dictionary that contains key‐value pairs from a text file

问题描述

我有一个文本文件(one.txt)，其中包含任意数量的键/值对(键和值之间用冒号分隔，例如x:17).这里是一些(减去数字):

I have a text file (one.txt) that contains an arbitrary number of key‐value pairs (where the key and value are separated by a colon – e.g., x:17). Here are some (minus the numbers):

1. mattis:turpis
2. Aliquam:配水
3. nonummy:ligula
4. Duis:ultricies
5. nonummy:pretium
6. urna:dolor
7. odio:mauris
8. lectus:per
9. quam:ridiculus
10. tellus:nonummy
11. consequat:metus

1. mattis:turpis
2. Aliquam:adipiscing
3. nonummy:ligula
4. Duis:ultricies
5. nonummy:pretium
6. urna:dolor
7. odio:mauris
8. lectus:per
9. quam:ridiculus
10. tellus:nonummy
11. consequat:metus

我需要打开文件并创建一个包含所有键值对的字典.

I need to open the file and create a dictionary that contains all of the key‐value pairs.

到目前为止，我已经打开了文件

So far I have opened the file with

file = []
with open('one.txt', 'r') as _:
    for line in _:
        line = line.strip()
        if line:
            file.append(line)

我以这种方式打开它，以消除文本文件中的换行符和最后一个黑线.我得到了python中的键/值对的列表.

I opened it this way to get rid of new line characters and the last black line in the text file. I am given a list of the key-value pairs within python.

我不确定如何使用列表键值对创建字典. 我尝试过的一切都给我一个错误.有些人说的是

I am not sure how to create a dictionary with the list key-value pairs. Everything I have tried gives me an error. Some say something along the lines of

ValueError:字典更新序列元素#0的长度为1；需要2个

ValueError: dictionary update sequence element #0 has length 1; 2 is required

推荐答案

使用str.split():

with open('one.txt') as f:
    d = dict(l.strip().split(':') for l in f)

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