根据字符串的长度对静态数组中的字符串进行排序会导致崩溃? |错误的分配/访问权限| [英] Sorting Strings in a static array based on their length crashes? |wrong allocation/access|
问题描述
我想创建一个字符串数组,并根据它们的长度(最小->最大)对它们进行排序,但是程序在所有输入后都崩溃了.
并且绕过元素0(在输入过程中直接从元素1开始)
I wanted to make an array of strings and sort them in order based on their length (smallest -> biggest) but the program crashes after all inputs.
And also it bypasses Element 0 (starts directly from element 1 during input)
#include <stdio.h>
#include <stdlib.h>
main()
{
int i,j,N;
printf("\nInput amount of alphanumericals: ");
scanf("%d",&N);
{
int min;
char *swap=(char*)malloc(sizeof(char)*150);
char *A[N],**temp;
for(i=0;i<N;i++)
*(A+i)=malloc(sizeof(char)*N);//Error Here
temp=A;
for(i=0;i<N;i++){
printf("\nInput %d element:",i+1);
fgets(temp+i,150,stdin);//And Here
}
printf("\n\nData [");
for(i=0;i<N;i++)
printf(" %s",A[i]);
printf(" ]\n\n");
//insertion sort
for(i=0;i<N;i++){
min=i;
for(j=i+1;j<N;j++){
if(strcmp(A[j],A[min])<0){
min=j;
}
}
if(min!=i){
swap=A[i];
A[i]=A[min];
A[min]=swap;
}
}
free(swap);
printf("\n\nInsertion Sorted Data [");
for(i=0;i<N;i++)
printf(" %s",A[i]);
printf(" ]");
}
return 0;
}
推荐答案
此错误:
for(i=0;i<N;i++)
*(A+i)=malloc(sizeof(char)*N);//Error Here
我是用g ++编译器复制的,如果您也是这种情况,即您也使用g ++进行编译,则将强制类型转换为char *:
i reproduced with g++ compiler, if this is your case also i.e. you also compiling with g++ add casting to char* :
*(A+i)= (char*) malloc(sizeof(char)*N);//Error Here
第二个问题是因为您尝试传递char **而不是char * 解决:
The second issue is because you trying to pass char** instead of char* fix :
fgets(*(temp+i),150,stdin);//And Here
在scanf(%d",& N);之后也加上括号.限制变量 min 和 swap 的范围,因此以后的所有内容都不可见.
Also brackets after scanf("%d",&N); limits scope of variables min and swap , so later should not be visible at all.
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