根据子字符串中的数字对字符串进行排序 [英] Sort a string depending on the number in the substring

问题描述

我有一个像这样的字符串is2 Thi1s T4est 3a，我需要对它进行排序，所以
数组看起来像Thi1s is2 3a T4est。 Number可以出现在字符串中的任何位置。我知道如何按字母顺序排序字符串以及如何对数字数组进行排序，但在这种情况下如何完成？有没有一种方法可以帮助它在数字上忽略字母？
我一直试图完成这项任务一段时间，任何帮助都将不胜感激！

I have a string like this "is2 Thi1s T4est 3a", I would need to sort it, so the array would look like this "Thi1s is2 3a T4est ". Number can appear anywhere in the string. I know how to sort strings alphabetically and how to sort an array of numbers, but how is it done in this case? Is there a method that helps sort it numerically ignoring letters? I have been trying to accomplish this task for a while, any help will be appreciated!

推荐答案

你可以拆分在空格和 sort 基于每个字符串中存储的数值：

You could split on spaces and sort based on the numeric value stored in each string:

let words = "is2 Thi1s T4est 3a".split(' ');
words.sort((a, b) => a.replace(/[^\d]+/g, '') - b.replace(/[^\d]+/g, ''));
console.log(words.join(' '));

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