在 Bash 中用数字对字符串进行排序 [英] Sorting strings with numbers in Bash
问题描述
我经常想对包含数字的字符串进行排序,这样在排序时,例如abc_2, abc_1, abc_10
结果是abc_1, abc_2, abc_10
.我见过的每种排序机制都按照 abc_1, abc_10, abc_2
排序,即从左边开始一个字符一个字符地排序.
I've often wanted to sort strings with numbers in them so that, when sorting e.g. abc_2, abc_1, abc_10
the result is abc_1, abc_2, abc_10
. Every sort mechanism I've seen sorts as abc_1, abc_10, abc_2
, that is character by character from the left.
有没有什么有效的排序方式来得到我想要的结果?查看每个字符,确定它是否是数字,从后续数字中构建子字符串并将其作为数字排序的想法太可怕了,无法在 bash
中考虑.
Is there any efficient way to sort to get the result I want? The idea of looking at every character, determining if it's a numeral, building a substring out of subsequent numerals and sorting on that as a number is too appalling to contemplate in bash
.
有没有胡子 *nix 大师使用 --sensible_numeric
选项实现了 sort
的替代版本?
Has no bearded *nix guru implemented an alternative version of sort
with a --sensible_numerical
option?
推荐答案
执行这个
sort -t _ -k 2 -g data.file
- -t 分隔符
- -k 键/列
- -g 一般数字排序
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