使用参数启动Infopath表单 [英] Launch Infopath form with parameter

问题描述

可以使用以下方法打开带参数的Infopath表单:

Opening an Infopath form with parameter can be done like this:

System.Diagnostics.Process.Start(PathToInfopath + "infopath.exe", "Template.xsn /InputParameters Id=123");

但这需要我知道Infopath.exe的路径，该路径随Office的每个版本而变化.有没有一种方法可以简单地启动模板并传递参数?还是有找到Infopath.exe驻留位置的标准方法?

But that requires I know the path to Infopath.exe which changes with each version of Office. Is there a way to simply launch the template and pass a parameter? Or is there a standard way to find where Infopath.exe resides?

推荐答案

以下是有关查找Office Apps安装路径的文章:

Here's an article about finding the install path for Office Apps:

http://support.microsoft.com/kb/234788

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