使用R将数据集中的多列重新排列为一列 [英] Re-arrange multiple columns in a data set into one column using R

问题描述

我想将其中一个数据集的三列合并为一个变量名称为"al_anim"的列，并删除所有重复项，将值(动物ID)从最低到最高排列，然后将每只动物的编号从1重新编号为N在变量名"new_id"下.

I would like to combine three columns in one of my data sets into one with variable name "al_anim" and remove any duplicates, rank the values (animal ids) from lowest to highest, and re-number each animal from 1 to N under the variable name "new_id".

 anim1 <- c(1456,2569,5489,1456,4587)
 anim2 <- c(6531,6987,6987,15487,6531)
 anim3 <- c(4587,6548,7894,3215,8542)
 mydf <- data.frame(anim1,anim2,anim3)

任何帮助将不胜感激！

巴兹

推荐答案

在您的示例中使用mydf:

mydf <- data.frame(anim1, anim2, anim3)

堆叠数据:

sdf <- stack(mydf)

然后使用unique()

uni <- unique(sdf[, "values"])

然后这将为他们提供一个新的动物ID

and then this will get them a new animal id

new_id <- as.numeric(as.factor(sort(uni)))

这将给出:

> new_id
 [1]  1  2  3  4  5  6  7  8  9 10 11

然而，那完全是微不足道的； seq_along(uni)使您轻松到达那里.所以我想知道你是否想要

However that is totally trivial; seq_along(uni) gets you there far more easily. So I wonder if you want

newdf <- data.frame(anim = sort(uni), new_id = seq_along(uni))
merge(sdf, newdf, by.x = "values", by.y = "anim")

给出:

> merge(sdf, newdf, by.x = "values", by.y = "anim")
   values   ind new_id
1    1456 anim1      1
2    1456 anim1      1
3    2569 anim1      2
4    3215 anim3      3
5    4587 anim1      4
6    4587 anim3      4
7    5489 anim1      5
8    6531 anim2      6
9    6531 anim2      6
10   6548 anim3      7
11   6987 anim2      8
12   6987 anim2      8
13   7894 anim3      9
14   8542 anim3     10
15  15487 anim2     11

您的问题中存在一定的歧义，可以通过提供预期的结果/输出来缓解这种歧义.

There is an amount of ambiguity in your Question which could be alleviated by giving an expected result/output.

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