dplyr根据向量中的名称更改多列 [英] dplyr mutate multiple columns based on names in vectors
问题描述
我想通过使用dplyr's mutate
函数将两列彼此相乘.
I want to multiply two columns with each other by using dplyr's mutate
function.
但我不想使用每个突变条件写新行,而是使用存储在向量var1
和var2
中的列的名称.例如,最后我想在现有的bankdata
中有一个名为result1
的附加列,该列包含通过将现金和贷款列彼此相乘得到的结果.这将继续直到创建了3个新列.
But instead of writing a new line for each mutate conditions I would like to use the names of the columns stored in the vectors var1
and var2
. For example in the end I want to have a additional column in my existing bankdata
with the name result1
which contains the result by multiplying the columns cash and loans with each other. This shall be continued until 3 new columns have been created.
可复制的代码:
bankname <- c("Bank A", "Bank B", "Bank C", "Bank D", "Bank E")
bankid <- c(1, 2, 3, 4, 5)
year <- c(1881, 1881, 1881, 1881, 1881)
totass <- c(244789, 195755, 107736, 170600, 32000000)
cash <- c(7250, 10243, 13357, 35000, 351266)
bond <- c(20218, 185151, 177612, 20000, 314012)
loans <- c(29513, 2800, NA, 5000, NA)
bankdata <- data.frame(bankname, bankid, year, totass, cash, bond, loans)
向量 var1 和 var2 包含我要相乘的列名称(cash*loans, bond*cash, loans*bankid
),而 output 是新列的名称:
Vectors var1 and var2 contain the column names I want to multiply (cash*loans, bond*cash, loans*bankid
) and output is the name of the new column:
var1 <- c("cash", "bond", "loans")
var2 <- c("loans","cash", "bankid")
output <- c("result1", "result2", "result3")
我想做类似的事情:
bankdata %>%
mutate_at(.funs = funs(output = var1*var2), vars(var1, var2))
bankdata %>%
mutate_at(.funs = funs(result1 = cash*., result2 = bond*., result3 = loans*.), vars(var2))
推荐答案
Using tidyeval
approach, we build a function which can take strings as inputs then create new column. Note the use of rlang::sym
and !!
(bang bang).
此后,我们可以使用purrr::pmap_dfc
遍历var1
,var2
创建其名称由output
After that we can use purrr::pmap_dfc
to loop through var1
, var2
to create new columns whose names supplied by output
library(tidyverse)
bankname <- c("Bank A", "Bank B", "Bank C", "Bank D", "Bank E")
bankid <- c(1, 2, 3, 4, 5)
year <- c(1881, 1881, 1881, 1881, 1881)
totass <- c(244789, 195755, 107736, 170600, 32000000)
cash <- c(7250, 10243, 13357, 35000, 351266)
bond <- c(20218, 185151, 177612, 20000, 314012)
loans <- c(29513, 2800, NA, 5000, NA)
bankdata <- data.frame(bankname, bankid, year, totass, cash, bond, loans)
originalNames <- names(bankdata)
var1 <- c("cash", "bond", "loans")
var2 <- c("loans","cash", "bankid")
output <- c("result1", "result2", "result3")
my_mutate <- function(df, var1, var2, output) {
var1 <- rlang::sym(var1)
var2 <- rlang::sym(var2)
output <- rlang::sym(output)
df <- df %>%
mutate(!! output := !! var1 * !! var2)
return(df)
}
# test
my_mutate(bankdata, var1[1], var2[1], output[1])
#> bankname bankid year totass cash bond loans result1
#> 1 Bank A 1 1881 244789 7250 20218 29513 213969250
#> 2 Bank B 2 1881 195755 10243 185151 2800 28680400
#> 3 Bank C 3 1881 107736 13357 177612 NA NA
#> 4 Bank D 4 1881 170600 35000 20000 5000 175000000
#> 5 Bank E 5 1881 32000000 351266 314012 NA NA
# loop through 3 lists simultaneously
# keep only original and result* columns
pmap_dfc(list(var1, var2, output), ~ my_mutate(bankdata, ..1, ..2, ..3)) %>%
select(!! originalNames, starts_with("result"))
#> bankname bankid year totass cash bond loans result1 result2
#> 1 Bank A 1 1881 244789 7250 20218 29513 213969250 146580500
#> 2 Bank B 2 1881 195755 10243 185151 2800 28680400 1896501693
#> 3 Bank C 3 1881 107736 13357 177612 NA NA 2372363484
#> 4 Bank D 4 1881 170600 35000 20000 5000 175000000 700000000
#> 5 Bank E 5 1881 32000000 351266 314012 NA NA 110301739192
#> result3
#> 1 29513
#> 2 5600
#> 3 NA
#> 4 20000
#> 5 NA
由 reprex软件包(v0.2.0)创建于2018-04-18.
Created on 2018-04-18 by the reprex package (v0.2.0).
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