MySQL COUNT DISTINCT [英] MySQL COUNT DISTINCT
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问题描述
我正试图收集昨天在我的客户服务中进行的不重复访问的次数,然后对它们进行计数.
I'm trying to collect the number of distinct visits in my cp yesterday, then count them.
SELECT
DISTINCT `user_id` as user,
`site_id` as site,
`ts` as time
FROM
`cp_visits`
WHERE
ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)
由于某种原因,这会以相同的站点ID提取多个结果....我如何仅提取和计算不同的site_id cp登录数?
For some reason this is pulling multiple results with the same site id....how do i only pull and count the distinct site_id cp logins?
推荐答案
Select
Count(Distinct user_id) As countUsers
, Count(site_id) As countVisits
, site_id As site
From cp_visits
Where ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)
Group By site_id
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