MySQL 计数 DISTINCT [英] MySQL COUNT DISTINCT

问题描述

我正在尝试收集昨天在我的 cp 中的不同访问次数，然后计算它们.

I'm trying to collect the number of distinct visits in my cp yesterday, then count them.

SELECT
    DISTINCT `user_id` as user,
    `site_id` as site,
    `ts` as time
FROM
    `cp_visits`
WHERE
    ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)

出于某种原因，这是提取具有相同站点 ID 的多个结果....我如何只提取和计算不同的 site_id cp 登录?

For some reason this is pulling multiple results with the same site id....how do i only pull and count the distinct site_id cp logins?

推荐答案

 Select
     Count(Distinct user_id) As countUsers
   , Count(site_id) As countVisits
   , site_id As site
 From cp_visits
 Where ts >= DATE_SUB(NOW(), INTERVAL 1 DAY)
 Group By site_id

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