检查两个日期是否不在另一个日期+ MYSQl之间 [英] Check two date was not between two another date + MYSQl

问题描述

我正在查询酒店预订和预订系统的查询，但是在选择两个日期之间未预订房间时遇到了问题. 我的查询与此类似，但是它不能正常工作，查询返回注意，但实际上我有3个房间，房间类型为1. SQL提琴手: http://sqlfiddle.com/#!2/b97419

I am writhing a query for a hotel reservation and booking system but I got a problem with selecting rooms was not reserved between two date . my query is alike this but it's not working as well and query return noting but actually I have 3 room with room type 1 . Sql fiddle : http://sqlfiddle.com/#!2/b97419

SELECT tbl_room.room_no, tbl_room.type_id, tbl_Reservation.room_id
FROM tbl_room
LEFT JOIN tbl_Reservation ON tbl_room.id = tbl_Reservation.room_id
WHERE (
(
tbl_Reservation.checkin_data < '" . $checkin . "'
AND tbl_Reservation.checkout_data < '" . $checkin . "'
)
OR (
tbl_Reservation.checkin_data > '" . $checkout . "'
AND tbl_Reservation.checkout_data > '" . $checkout . "'
)
)
AND tbl_room.type_id =1

感谢您的帮助，对不起我的英语不好.

thanks for your helping and sorry for my bad english .

推荐答案

尝试类似的方法

SELECT 
    tbl_room.room_no, 
    tbl_room.type_id, 
    tbl_room.id,

    tr.id as reserv_status

FROM tbl_room

 LEFT JOIN tbl_Reservation tr ON tbl_room.id = tr.room_id AND 
           (
             (tr.checkin_data <= "'$checkin'" AND tr.checkout_data >= "'$checkin'")
             OR
             (tr.checkin_data <= "'$checkout'" AND tr.checkout_data >= "'$checkout'")
           )

 WHERE 

 tbl_room.type_id =1  AND tr.id IS NULL

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