回声/返回在变量前添加空格 [英] Echo/return is adding whitespace before variable

问题描述

我有一些代码，该代码从数据库中获取信息，然后创建图像的路径并返回它，并将其用作另一页上的img src.

I have some code, which grabs information from a database, then creates a path to an image and returns it, which I use as the img src on another page.

功能如下:

function getMainImage ()
{
    $query = "SELECT * FROM pictures WHERE username = '$_SESSION[username]' AND main = 'y' LIMIT 1";
    include 'connect.php';
    $result = mysql_query($query) or die (mysql_error());
    mysql_close($dbhandle);
    $row = mysql_fetch_assoc($result);
    $path = "images/t_$row[username]_$row[number].$row[ext]";
    return $path;
}
<img src="<?php echo getMainImage(); ?>" width="40" height="40" />

查看页面源时的输出为:

The output when looking at the page source is:

<img src=" images/t_image_3.jpg" width="40" height="40" />

该函数在"images/"之前添加了一个额外的空间.我试过修剪路径，甚至在调用它时都修剪函数，但是都没有用.有什么想法吗?

There is an extra space being added from the function before "images/". I've tried trimming the path, and even trimming the function when calling it, but neither worked. Any ideas?

推荐答案

包括

您几乎可以看到的空白来自此行:

include

The whitespace you're seeing almost certainly comes from this line:

include 'connect.php';

检查文件connect.php中的内容，并在打开<?php之前删除所有空格，如果它具有?>，则只需将其删除.

Check what you have in the file connect.php, and delete any whitespace before the opening <?php, and if it has a ?>, simply delete it.

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