我如何preserve领先的回声空格的shell脚本？ [英] How do I preserve leading whitespaces with echo on a shell script?

问题描述

我有一个源文件是已经合并在一起的多个文件的组合。我的脚本应该将它们分开成原来的单个文件。

每当遇到以FILENM开始的行，这意味着它的下一个文件的开头。

在所有文件的详细线路是固定的宽度;所以，我目前遇到在那里，与领先的空格开始的行被截断时，它不应该被截断的问题。

我如何提高这个剧本保留了领先的空格？

 而读线
做
    线型=`回声$线|切-c1-6`
    如果[$线型==FILENM];然后
       文件名=`回声$线|切-C7-`
    其他
       回声$行＆GT;＆GT; $文件路径/文件名$
    科幻
完成＆LT; $文件路径/的资源文件
 

解决方案

的前导空格，因为删除读拆分输入单词。为了解决这个问题，将 IFS 变量空字符串。像这样的：

  OLD_IFS =$ IFS
IFS =
而读线
做
    ...
完成＆LT; $文件路径/的资源文件
IFS =$ OLD_IFS
 

I have a source file that is a combination of multiple files that have been merged together. My script is supposed to separate them into the original individual files.

Whenever I encounter a line that starts with "FILENM", that means that it's the start of the next file.

All of the detail lines in the files are fixed width; so, I'm currently encountering a problem where a line that starts with leading whitespaces is truncated when it's not supposed to be truncated.

How do I enhance this script to retain the leading whitespaces?

while read line         
do         
    lineType=`echo $line | cut -c1-6`
    if [ "$lineType" == "FILENM" ]; then
       fileName=`echo $line | cut -c7-`
    else
       echo "$line" >> $filePath/$fileName
    fi   
done <$filePath/sourcefile

解决方案

The leading spaces are removed because read splits the input into words. To counter this, set the IFS variable to empty string. Like this:

OLD_IFS="$IFS"
IFS=
while read line         
do
    ...
done <$filePath/sourcefile
IFS="$OLD_IFS"

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