如何根据numpy中的条件拆分数组? [英] How to split an array according to a condition in numpy?

问题描述

例如，我有一个ndarray:

a = np.array([1, 3, 5, 7, 2, 4, 6, 8])

现在我想将a分为两部分，一个是所有数字< 5，另一个是所有> = 5:

Now I want to split a into two parts, one is all numbers <5 and the other is all >=5:

[array([1,3,2,4]), array([5,7,6,8])]

当然，我可以遍历a并创建两个新数组.但是我想知道numpy是否提供了一些更好的方法?

Certainly I can traverse a and create two new array. But I want to know does numpy provide some better ways?

类似地，对于多维数组，例如

Similarly, for multidimensional array, e.g.

array([[1, 2, 3],
       [4, 5, 6],
       [7, 8, 9],
       [2, 4, 7]])

我想根据第一列< 3和> = 3对其进行拆分，结果是:

I want to split it according to the first column <3 and >=3, which result is:

[array([[1, 2, 3],
        [2, 4, 7]]), 
 array([[4, 5, 6],
        [7, 8, 9]])]

有没有更好的方法来遍历它?谢谢.

Are there any better ways instead of traverse it? Thanks.

推荐答案

import numpy as np

def split(arr, cond):
  return [arr[cond], arr[~cond]]

a = np.array([1,3,5,7,2,4,6,8])
print split(a, a<5)

a = np.array([[1,2,3],[4,5,6],[7,8,9],[2,4,7]])
print split(a, a[:,0]<3)

这将产生以下输出:

[array([1, 3, 2, 4]), array([5, 7, 6, 8])]

[array([[1, 2, 3],
       [2, 4, 7]]), array([[4, 5, 6],
       [7, 8, 9]])]

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