拆分数组中的C / C ++块 [英] Split array into chunks in C/C++

问题描述

我要寻找一种方式来拆分数组中的C / C多个阵列++，与标准的Win32和C / C ++的功能。

下面是一个例子，我是多么文件读入数组中。

 使用命名空间std;LPSTR File_To_Read =的file.exe;
DWORD File_To_Read_Size = NULL;
DWORD inputSize = NULL;
PBYTE inputData = NULL;ifstream的输入（File_To_Read，ifstream的二进制:: | :: ifstream的ATE）;
File_To_Read_Size =的static_cast＆所述; DWORD＆GT;（input.tellg（））;
input.seekg（input.beg）;inputData =新的字节[File_To_Read_Size]
input.read（reinter pret_cast＆LT;字符*＆GT;（inputData），File_To_Read_Size）;
input.close（）;
 

现在我要分割inputData这样。

  DWORD inputSize_part1;
DWORD inputSize_part2;
DWORD inputSize_part3;PBYTE inputData_part1;
PBYTE inputData_part2;
PBYTE inputData_part3;
 

因此​​，在以后我也可以把他们重新走到一起。

我应该如何进行？我会显示一个例子code什么，我都试过了，但我的code不会使没有太大意义的各位专家。

编辑：
@IKH块大小应该是大约相同的尺寸。因此，如果inputData是33KB，则inputData_part1（和inputSize_part1）应11KB，inputData_part2（和inputSize_part2）应11KB，等等。那么，到底会有3倍11KB阵列和DWORDS对它们的大小。

解决方案

  DWORD inputSize_part1 = inputSize / 3;
DWORD inputSize_part2 = inputSize / 3;
DWORD inputSize_part3 = inputSize  -  inputSize_part1  -  inputSize_part2;PBYTE inputData_part1 = inputData;
PBYTE inputData_part2 = inputData + inputSize_part1;
PBYTE inputData_part3 = inputData + inputSize_part1 + inputSize_part2;
 

现在您有三个指针和三个尺寸为三个部分：前两个是第三或略少，而第三组块可稍大如果原始不整除。你需要删除[] inputData 当你使用所有的块做的。

I am looking for a way to split an array into multiple arrays in C/C++, with standard Win32 and C/C++ functions.

Here's an example, how I read a file into the array.

using namespace std;

LPSTR File_To_Read = "FILE.exe"; 
DWORD File_To_Read_Size = NULL;
DWORD inputSize = NULL;
PBYTE inputData = NULL;

ifstream input(File_To_Read, ifstream::binary | ifstream::ate);
File_To_Read_Size = static_cast<DWORD>(input.tellg());
input.seekg(input.beg);

inputData = new BYTE[File_To_Read_Size];
input.read(reinterpret_cast<char*>(inputData), File_To_Read_Size);
input.close();

Now I want to split the inputData like this.

DWORD inputSize_part1;
DWORD inputSize_part2;
DWORD inputSize_part3;

PBYTE inputData_part1;
PBYTE inputData_part2;
PBYTE inputData_part3;

So in the later I can also put them back together.

How should I proceed? I would show an example code what I have tried, but my code would not make not much sense for you experts.

Edit: @IKH Chunk sizes should be around the same size. So if inputData is 33kb, then inputData_part1(and inputSize_part1) should be 11kb, inputData_part2(and inputSize_part2) should be 11kb, and so on. So in the end there would be 3x 11kb arrays and DWORDS for their sizes.

解决方案

DWORD inputSize_part1 = inputSize / 3;
DWORD inputSize_part2 = inputSize / 3;
DWORD inputSize_part3 = inputSize - inputSize_part1 - inputSize_part2;

PBYTE inputData_part1 = inputData;
PBYTE inputData_part2 = inputData + inputSize_part1;
PBYTE inputData_part3 = inputData + inputSize_part1 + inputSize_part2;

Now you have three pointers and three sizes for the three chunks: the first two are a third or slightly less, and the third chunk may be slightly larger if the original was not evenly divisible. You'll need to delete[] inputData when you're doing using all of the chunks.

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