在连续日期的子数组中拆分数组 [英] Split an array in sub arrays of consecutive dates

问题描述

对于租金申请，我有一个数组$ date这样：

  Array 
（
 [2013-07-19] => 1 
 [2013-07-21] => 3 
 [2013-07-23] => 2 
 [2013-07 -24] => 4 
 [2013-07-25] => 4 
 [2013-07-26] => 2 
 [2013-07-27] => ; 2 
 [2013-07-30] => 3 
 [2013-07-31] => 1 
）
  pre> 
 
 
日期是关键字，值是特定产品当天租金的数量
 
 
 
如何将这个数组拆分成包含每个连续列表的多个子数组？ 
像这样：
  Array 
（
 
 [0] => ; Array 
（
 [2013-07-19] => 1 
）
 
 [1] =>数组
（
 [2013-07-21] => 3 
）
 
 [2] => Array 
（
 [2013-07-23] => ; 2 
 [2013-07-24] => 4 
 [2013-07-25] => 4 
 [2013-07-26] => 2 
 [2013-07-27] => 2 
）
 
 [3] =>数组
（
 [2013-07-30] => ; 3 
 [2013-07-31] => 1 
）
 
）
  
 
 
解决方案
你可以这样做：
  $ data = array（
'2013-07-19'=> 1，
'2013-07-21'=> 3，
'2013-07-23'= > 2，
'2013-07-24'=> 4，
'2013-07-25'=> 4，
'2013-07-26'=> 2，
 '20 13-07-27'=> 2，
'2013-07-30'=> 3，
'2013-07-31'=> 1 
）; 
 
 $ result = array（）; 
 $ ref = new DateTime（'1821-11-11'）; 
 foreach（$ data as $ datum => $ nb）{
 if（$ ref-> add（new DateInterval（'P1D'）） - > format（'Ym-d' ！= $ datum）{
 $ result [] = array（）; 
 $ ref = new DateTime（$ datum）; 
} 
 $ result [array_pop（array_keys（$ result））] [$ datum] = $ nb; 
} 
 print_r（$ result）; 
  
 
For a rent application, I have an array $dates like this:
Array
(
    [2013-07-19] => 1
    [2013-07-21] => 3
    [2013-07-23] => 2
    [2013-07-24] => 4
    [2013-07-25] => 4
    [2013-07-26] => 2
    [2013-07-27] => 2
    [2013-07-30] => 3
    [2013-07-31] => 1
)
The date is the key, and the values are the number of items rent in that day for a specific product

How can I split this array in many sub arrays containing each a list of consecutive days?
Like this:
Array
(

    [0] => Array
        (
            [2013-07-19] => 1
        )

    [1] => Array
        (
            [2013-07-21] => 3
        )

    [2] => Array
        (
            [2013-07-23] => 2
            [2013-07-24] => 4
            [2013-07-25] => 4
            [2013-07-26] => 2
            [2013-07-27] => 2
        )

    [3] => Array
        (
            [2013-07-30] => 3
            [2013-07-31] => 1
        )

)

解决方案
you can do it like this:
$data = array(
  '2013-07-19' => 1,
  '2013-07-21' => 3,
  '2013-07-23' => 2,
  '2013-07-24' => 4,
  '2013-07-25' => 4,
  '2013-07-26' => 2,
  '2013-07-27' => 2,
  '2013-07-30' => 3,
  '2013-07-31' => 1
);

$result = array();
$ref = new DateTime('1821-11-11');
foreach ($data as $datum => $nb) {
    if ($ref->add(new DateInterval('P1D'))->format('Y-m-d')!=$datum) {
        $result[] = array(); 
        $ref = new DateTime($datum);
    }
    $result[array_pop(array_keys($result))][$datum] = $nb;
}
print_r($result);


                        
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