Python fsolve()抱怨形状.为什么? [英] Python fsolve() complains about shape. Why?

问题描述

具有函数f(x，y，z)，我需要求解限制f(x，y，z)= 0，然后对其进行绘制.我试图为每对(y，z)找到f(x，y，z)= 0的值x:

Having the function f(x,y,z), I need to solve the restriction f(x,y,z) = 0 and then plot it. I tried to find for each pair (y,z) the value x for which f(x,y,z) = 0:

from numpy import *
from scipy.optimize import fsolve

def func(x,y,z):
    return x+y+z

y = linspace(0,1,100)
z = linspace(0,1,100)
x0 = zeros((y.size,z.size)) + 0.5 # the initial guess
yz = (y[:,newaxis],z[newaxis,:]) # the other parameters
x, info, iterations, message = fsolve(func,x0,yz)
contour(y,z,x)

Python(2.7.5)说"TypeError:fsolve:'func'参数'func'的输入和输出形状不匹配."

Python (2.7.5) says "TypeError: fsolve: there is a mismatch between the input and output shape of the 'func' argument 'func'."

但是，如果我自己进行测试，它会具有相同的形状:

But if I test it myself, it gives the same shape:

func(x0,y[:,newaxis],z[:,newaxis]).shape == x0.shape

返回True.

为什么fsolve()抱怨?

Why does fsolve() complain?

推荐答案

fsolve期望x参数和func的返回值是标量或一维数组.您必须修改代码才能使用平坦的x值.例如

fsolve expects the x argument and the return value of func to be a scalar or one-dimensional array. You'll have to modify your code to work with flattened x values. E.g.

def func(x, y, z):
    x = x.reshape(y.size, z.size)
    return (x + y + z).ravel()

和类似这样的内容调用fsolve:

and something like this for the call to fsolve:

sol, info, ier, mesg = fsolve(func, x0.ravel(), args=yz, full_output=True)
x = sol.reshape(y.size, z.size)

这篇关于Python fsolve()抱怨形状.为什么?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！