在Python中将列表转换为列向量 [英] Transforming a list to a column vector in Python

问题描述

我想知道是否有一个函数将列表X作为输入并输出对应于X的列向量?

I was wondering if there's a function that takes a list X as input and outputs a column vector corresponding to X?

(我环顾四周，我怀疑可能是np.matrix(X).T)

(I looked around and I suspect it might be: np.matrix(X).T )

推荐答案

我认为没有功能，但是有一个专用对象np.c_

I don't think there is a function, but there is a dedicated object, np.c_

>>> X = list('hello world')
>>> X
['h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd']
np.c_[X]
array([['h'],
       ['e'],
       ['l'],
       ['l'],
       ['o'],
       [' '],
       ['w'],
       ['o'],
       ['r'],
       ['l'],
       ['d']], dtype='<U1')

您也可以这样做(请注意额外的方括号)

You can also do (note the extra square brackets)

>>> np.array([X]).T

这篇关于在Python中将列表转换为列向量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！