iOS XMPP框架获取所有注册用户 [英] iOS XMPP framework get all registered users

问题描述

在我的聊天应用程序中，我希望获得所有在线注册用户.因此，每个人，不仅是我名单中的人，都是通过以下代码实现的:

In my chat application I want to get all online registered users. So everybody and not only people in my roster which is achieved with this code:

- (void)xmppStream:(XMPPStream *)sender didReceivePresence:(XMPPPresence *)presence {
// a buddy went offline/online
NSString *presenceType = [presence type]; // online/offline
NSString *myUsername = [[sender myJID] user];
NSString *presenceFromUser = [[presence from] user];
if (![presenceFromUser isEqualToString:myUsername]) {
    if ([presenceType isEqualToString:@"available"]) {
        [_chatDelegate newBuddyOnline:[NSString stringWithFormat:@"%@@%@", presenceFromUser, @"chat.denederlandsewateren.nl"]];
    } else if ([presenceType isEqualToString:@"unavailable"]) {
        [_chatDelegate buddyWentOffline:[NSString stringWithFormat:@"%@@%@", presenceFromUser, @"chat.denederlandsewateren.nl"]];
    }
}
}

使用此代码，用户只能看到其他朋友"用户，但我需要在该特定域上注册的所有用户. ejabberd有可能吗?

With this code the users only sees other users who are 'friends' but I need all users registered on this particular domain. Is this possible with ejabberd?

推荐答案

- (void)getAllRegisteredUsers {

    NSError *error = [[NSError alloc] init];
    NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/disco#items' node='all users'/>"
                                                            error:&error];
    XMPPIQ *iq = [XMPPIQ iqWithType:@"get"
                                 to:[XMPPJID jidWithString:@"DOMAIN"]
                          elementID:[xmppStream generateUUID] child:query];
    [xmppStream sendElement:iq];
}

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
{
    NSXMLElement *queryElement = [iq elementForName: @"query" xmlns: @"http://jabber.org/protocol/disco#items"];

    if (queryElement) {
        NSArray *itemElements = [queryElement elementsForName: @"item"];
        NSMutableArray *mArray = [[NSMutableArray alloc] init];
        for (int i=0; i<[itemElements count]; i++) {

            NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue];
            [mArray addObject:jid];
        }



    }

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