iOS XMPP群聊实施 [英] iOS XMPP group chat implementation
问题描述
我正在尝试使用robbiehanson XMPPframework创建聊天室。
I am trying to create chat room using robbiehanson XMPPframework.
由于我没有得到任何示例代码或文档，我自己尝试启动聊天室如下：
Since I didn't get any sample code or documentation, I made a try by myself to initiate a chat room as follows:
XMPPRoomMemoryStorage *rosterstorage = [[XMPPRoomMemoryStorage alloc] init];
XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:rosterstorage jid:[XMPPJID jidWithString:@"test@mycompany.com/room"] dispatchQueue:dispatch_get_main_queue()];
[xmppRoom configureRoomUsingOptions:nil];
[xmppRoom activate:[UIAppDelegate xmppStream]];
[xmppRoom addDelegate:UIAppDelegate
delegateQueue:dispatch_get_main_queue()];
[xmppRoom inviteUser:[XMPPJID jidWithString:jabberID] withMessage:@"Hi join room"];
但是我在控制台得到的响应为：
But I am getting the response in the console as :
RECV: <message xmlns="jabber:client" from="test@mycompany.com" to="user1@mycompany.com/42512304551337785705750233" type="error"><x xmlns="http://jabber.org/protocol/muc#user"><invite to="user2@mycompany.com"><reason>Hi join room</reason></invite></x><error code="503" type="cancel"><service-unavailable xmlns="urn:ietf:params:xml:ns:xmpp-stanzas"/></error></message>
任何人都有任何想法启动MUC ??有没有任何示例代码？任何帮助将不胜感激。谢谢。
Anybody have any idea to initiate MUC??Is there any sample code for this??Any help will be appreciated..Thanks in advance..
推荐答案
最后我明白了。它可能会帮助某人。在创建或加入会议室时，格式应为 yourRoomName@conference.YourDomainName.com 。会议是这里的关键词。
Finally I figured it out. It may help someone. While creating or joining the room, the format should be yourRoomName@conference.YourDomainName.com. The conference is the keyword here.
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