Python中的模运算符 [英] Modulo operator in Python

问题描述

以下代码中的模是做什么的?

What does modulo in the following piece of code do?

from math import *
3.14 % 2 * pi

我们如何计算浮点数的模数?

How do we calculate modulo on a floating point number?

推荐答案

当您具有表达式时:

a % b = c

这实际上意味着存在一个整数n，该整数会使c尽可能小，但不可为负.

It really means there exists an integer n that makes c as small as possible, but non-negative.

a - n*b = c

用手，您可以一遍又一遍地减去2(如果您的数字为负数，则可以加2)，直到最终结果是可能的最小正数:

By hand, you can just subtract 2 (or add 2 if your number is negative) over and over until the end result is the smallest positive number possible:

  3.14 % 2
= 3.14 - 1 * 2
= 1.14

此外，3.14 % 2 * pi被解释为(3.14 % 2) * pi.我不确定您是否要编写3.14 % (2 * pi)(在任何一种情况下，算法都是相同的.只需加/减，直到数字尽可能小为止).

Also, 3.14 % 2 * pi is interpreted as (3.14 % 2) * pi. I'm not sure if you meant to write 3.14 % (2 * pi) (in either case, the algorithm is the same. Just subtract/add until the number is as small as possible).

这篇关于Python中的模运算符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！