了解模运算符的结果:%% [英] Understanding the result of modulo operator: %%

问题描述

我正在寻找适用于R语言中%%运算符的方法.

I'm looking for the methodology which applied to %% operator in R language.

10 %% 10  # 0
20 %% 10  # 0

怀疑这两个结果:

10 %% 20  # 10
2 %% 8  # 2

您能帮我更好地了解最后两个结果吗?我有点困惑.

Can you help me to understand better on the last two results? I'm little confused.

推荐答案

没有问题:

10 = 1 * 10 + 0
20 = 2 * 10 + 0
10 = 0 * 20 + 10
2  = 0 * 8  + 2 

模数是+之后的数字.

通常，对于两个数字a和b，有

In general, for two numbers a and b, there is

a = floor(a / b) * b + (a %% b)

让我们编写一个玩具函数:

Let's write a toy function:

foo <- function(a,b) c(quotient = floor(a / b), modulo = a %% b)

foo(10, 10)
#quotient   modulo 
#   1        0 

foo(20, 10)
#quotient   modulo 
#   2        0 

foo(10, 20)
#quotient   modulo 
#   0       10 

foo(2, 8)
#quotient   modulo 
#   0        2 

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更新:我们也可以使用a %/% b，而不是使用floor(a / b)来获得商.

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Update: Instead of using floor(a / b) to get quotient, we can also use a %/% b.

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