在Oracle存储过程中访问另一个用户的表 [英] Accessing another user's table within an Oracle Stored Procedure

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本文介绍了在Oracle存储过程中访问另一个用户的表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在编写一个存储过程,以将数据从一个用户的表复制到另一种模式.基本上,它是一系列INSERT .. SELECT语句,例如:

I'm writing a stored procedure to copy data from one user's table to another schema. Basically, it is a series of INSERT .. SELECT statements such as this:

INSERT INTO GESCHAEFTE
  SELECT *
    FROM TURAT03.GESCHAEFTE
   WHERE kong_nr = 1234;

从sqlplus(或对我来说是TOAD ;-)发出问题时,此方法工作正常,因此我知道我具有足够的特权,但是当它是这样的存储过程的一部分时:

This works fine when issueing from sqlplus (or TOAD for me ;-)) so I know that I have sufficient privileges, but when this is part of stored procedure like this:

CREATE OR REPLACE FUNCTION COPY_KONG
    (pKongNr IN NUMBER)
    RETURN NUMBER
    AUTHID CURRENT_USER
IS
BEGIN
   INSERT INTO GESCHAEFTE
      SELECT *
       FROM TURAT03.GESCHAEFTE
       WHERE kong_nr = pKongNr;
END;

我收到一个Oracle错误:

I get an Oracle error:

[Error] ORA-00942 (11: 22): PL/SQL: ORA-00942: table or view does not exist

如您所见,我已经插入了AUTHID,但无济于事.

As you can see, I've already inserted an AUTHID, but to no avail.

我还能做什么?我在这里的想法几乎完结了.

What else can I do? I'm pretty much at the end of my ideas here.

推荐答案

必须为过程所有者授予直接访问基础对象的权限,

The owner of a procedure must be granted privilege to access the underlying objects directly, not through a role. To have the same level of access as your procedures, use the following commands:

SET ROLE NONE;

要从一个过程访问另一个表,您需要直接被授予SELECT权限,而不是通过角色来获得权限:

To access another table from a procedure, you need to be granted SELECT directly, not through a role:

GRANT SELECT ON TURAT03.GESCHAEFTE TO <your_user>;

汤姆·凯特(Tom Kyte)撰写的这篇文章包含其他信息.

这篇关于在Oracle存储过程中访问另一个用户的表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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