根据Oracle SQL中的营业时间计算营业时间 [英] calculate hours based on business hours in Oracle SQL

问题描述

我希望根据工作时间来计算任务开始和结束时间之间的时间.我有以下示例数据:

I am looking to calculate hours between a start and end of time of a task based on business hours. I have the following sample data:

TASK | START_TIME | END_TIME
A | 16-JAN-17 10:00 | 23-JAN-17 11:35
B | 18-JAN-17 17:53 | 19-JAN-17 08:00
C | 13-JAN-17 13:00 | 17-JAN-17 14:52
D | 21-JAN-17 10:00 | 30-JAN-17 08:52

我需要计算出两者之间的区别，但要基于以下工作时间:

and I need to work out the difference between the two but based on the following business hours:

Mon - Sat 08:00 - 18:00

我知道如何编写计算，但不确定如何将营业时间添加到计算中.

I know how to write the calculation but not sure what I do to add the business hours into the calculation.

任何建议将不胜感激.

推荐答案

使用相关的层次结构查询为每个工作日生成一行，然后对每一天的小时总数求和:

Use a correlated hierarchical query to generate one row for each work day and then sum the hours for each day:

SELECT task,
       COALESCE( SUM( end_time - start_time ), 0 ) * 24 AS total_hours
FROM   (
  SELECT task,
         GREATEST( t.start_time, d.column_value + INTERVAL '8' HOUR ) AS start_time,
         LEAST( t.end_time, d.column_value + INTERVAL '18' HOUR ) AS end_time
  FROM   your_table t
         LEFT OUTER JOIN
         TABLE(
           CAST(
             MULTISET(
               SELECT TRUNC( t.start_time + LEVEL - 1 )
               FROM   DUAL
               WHERE  TRUNC( t.start_time + LEVEL - 1 ) - TRUNC( t.start_time + LEVEL - 1, 'iw' ) < 6
               CONNECT BY TRUNC( t.start_time + LEVEL - 1 ) < t.end_time
             ) AS SYS.ODCIDATELIST
           )
         ) d
         ON (   t.end_time   > d.column_value + INTERVAL  '8' HOUR
            AND t.start_time < d.column_value + INTERVAL '18' HOUR )
)
GROUP BY task;

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