如何将程序包导入分组到单个自定义程序包中? [英] How do I group my package imports into a single custom package?
问题描述
通常在编写perl程序时.我曾经包括以下软件包.
Normally when I am writing the perl program . I used to include following package .
use strict ;
use warnings ;
use Data::Dumper ;
现在,我要这样,我不会在每个程序中都包含所有此软件包.为此
我将把所有这些包装放在自己的包装中.喜欢以下内容.
Now , I want like this, I will not include all this package for every program . for that
I will have these all package in my own package. like following.
my_packages.pm
package my_packages ;
{
use strict ;
use warnings ;
use Data::Dumper;
}
1;
因此,如果我在perl程序中添加my_packages.pm,则需要所有上述包.
So, that if I add my_packages.pm in perl program , it needs have all above packages .
实际上我已经做了这个实验.但是我无法得到这个东西. 这意味着当我使用my_packages时.我无法获得使用严格,使用警告,使用Data :: Dumper"的功能.
Actually I have done this experimentation . But I am not able get this things . which means when I am using my_packages . I am not able get the functionality of "use strict, use warnings , use Data::Dumper ".
有人帮助我解决了这个问题.....
Someone help me out of this problem.....
推荐答案
Have a look at ToolSet
, which does all the dirty import work for you.
pod中的用法示例:
Usage example from pod:
创建工具集:
# My/Tools.pm
package My::Tools;
use base 'ToolSet';
ToolSet->use_pragma( 'strict' );
ToolSet->use_pragma( 'warnings' );
ToolSet->use_pragma( qw/feature say switch/ ); # perl 5.10
# define exports from other modules
ToolSet->export(
'Carp' => undef, # get the defaults
'Scalar::Util' => 'refaddr', # or a specific list
);
# define exports from this module
our @EXPORT = qw( shout );
sub shout { print uc shift };
1; # modules must return true
使用工具集:
use My::Tools;
# strict is on
# warnings are on
# Carp and refaddr are imported
carp "We can carp!";
print refaddr [];
shout "We can shout, too!";
/I3az/
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