正确使用NSGetExecutablePath [英] Properly used NSGetExecutablePath

问题描述

我尝试在运行时获取我的应用程序的路径.我从C找到了一些旧资料，并将其相应地转换为函数参数类型定义:

I try to get the path to my application at runtime. I found some old sources from C and converted it accordingly to the functions parameter type definition:

var path = [Int8] (count:1024, repeatedValue: 0)
var bufsize : UInt32 = 1024

if _NSGetExecutablePath(&path, &bufsize) == 0 {
println("executable path is \(path)")
}

它可以运行，但是我需要一个Int8数组，而不是一个字符串.因此，我必须搜索字符链的末尾并将其转换回字符串.在SWIFT中使用此功能的正确方法是什么?

It runs, but I need an Int8 array, not a string. So I have to search for the end of the character chain and convert it back to a string. What is the correct way to use this function in SWIFT?

推荐答案

您需要从C字符串创建Swift字符串

You need to create a Swift String from a C String

let executablePath = String(CString: path, encoding: NSASCIIStringEncoding)!
println("executable path is \(executablePath)")

但是有一种更简单的方法来获取可执行文件的路径

But there is an easier way to get the path to the executable

let executablePath = Bundle.main.executablePath!

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