带有特殊字符的名称的正则表达式(Unicode) [英] Regex for names with special characters (Unicode)

问题描述

好的，我整天都在阅读正则表达式，但仍然不太了解它.我想做的是验证名称，但是我在互联网上可以找到的功能仅使用[a-zA-Z]，而忽略了我需要接受的字符.

Okay, I have read about regex all day now, and still don't understand it properly. What i'm trying to do is validate a name, but the functions i can find for this on the internet only use [a-zA-Z], leaving characters out that i need to accept to.

我基本上需要一个正则表达式来检查名称至少是两个单词，并且不包含数字或特殊字符(例如!"#¤%&/()=...)，但是这些单词可以包含æ，é，Â等字符. ..

I basically need a regex that checks that the name is at least two words, and that it does not contain numbers or special characters like !"#¤%&/()=..., however the words can contain characters like æ, é, Â and so on...

可接受的名称示例为:"JohnElkjærd"或AndréSvenson"
不可接受的名称为:" Hans "，"H 4 nn 3 Andersen"或"Martin Henriksen ！"

An example of an accepted name would be: "John Elkjærd" or "André Svenson"
An non-accepted name would be: "Hans", "H4nn3 Andersen" or "Martin Henriksen!"

如果很重要，我使用javascript .match()函数客户端，并且只想在负面"服务器端使用php的preg_replace(). (删除不匹配的字符).

If it matters i use the javascript .match() function client side and want to use php's preg_replace() only "in negative" server side. (removing non-matching characters).

任何帮助将不胜感激.

更新:
好的，感谢 Alix Axel的回答我扮演了重要的角色下来，服务器端.

Update:
Okay, thanks to Alix Axel's answer i have the important part down, the server side one.

但是，正如 LightWing的答案中的页面所示，我找不到关于javascript的unicode支持的任何信息，所以我最终为客户端提供了一半的解决方案，只是检查了至少两个单词和最少5个字符，如下所示:

But as the page from LightWing's answer suggests, i'm unable to find anything about unicode support for javascript, so i ended up with half a solution for the client side, just checking for at least two words and minimum 5 characters like this:

if(name.match(/\S+/g).length >= minWords && name.length >= 5) {
  //valid
}

一种替代方法是按照中的建议指定所有Unicode字符. shifty的答案，与上面的解决方案一样，我最终可能会做类似的事情，但这有点不切实际.

An alternative would be to specify all the unicode characters as suggested in shifty's answer, which i might end up doing something like, along with the solution above, but it is a bit unpractical though.

推荐答案

尝试以下正则表达式:

^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$

在PHP中，这表示为:

In PHP this translates to:

if (preg_match('~^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$~u', $name) > 0)
{
    // valid
}

您应该这样阅读:

^   # start of subject
    (?:     # match this:
        [           # match a:
            \p{L}       # Unicode letter, or
            \p{Mn}      # Unicode accents, or
            \p{Pd}      # Unicode hyphens, or
            \'          # single quote, or
            \x{2019}    # single quote (alternative)
        ]+              # one or more times
        \s          # any kind of space
        [               #match a:
            \p{L}       # Unicode letter, or
            \p{Mn}      # Unicode accents, or
            \p{Pd}      # Unicode hyphens, or
            \'          # single quote, or
            \x{2019}    # single quote (alternative)
        ]+              # one or more times
        \s?         # any kind of space (0 or more times)
    )+      # one or more times
$   # end of subject

老实说，我不知道如何将其移植到Javascript，我什至不确定Javascript是否支持Unicode属性，但是在PHP PCRE中，这似乎完美地工作@ IDEOne.com :

I honestly don't know how to port this to Javascript, I'm not even sure Javascript supports Unicode properties but in PHP PCRE this seems to work flawlessly @ IDEOne.com:

$names = array
(
    'Alix',
    'André Svenson',
    'H4nn3 Andersen',
    'Hans',
    'John Elkjærd',
    'Kristoffer la Cour',
    'Marco d\'Almeida',
    'Martin Henriksen!',
);

foreach ($names as $name)
{
    echo sprintf('%s is %s' . "\n", $name, (preg_match('~^(?:[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s[\p{L}\p{Mn}\p{Pd}\'\x{2019}]+\s?)+$~u', $name) > 0) ? 'valid' : 'invalid');
}

很抱歉，我无法在Javascript部分方面为您提供帮助，但可能有人会在这里提供帮助.

I'm sorry I can't help you regarding the Javascript part but probably someone here will.

验证:

• JohnElkjærd
• 安德烈·斯文森
• 马可·达美(Marco d'Almeida)
• 克里斯托弗·拉库尔

无效:

• 汉斯
• H4nn3安徒生
• 马丁·亨里克森！

要替换无效字符，尽管我不确定为什么需要这样做，您只需要对其稍作更改即可:

To replace invalid characters, though I'm not sure why you need this, you just need to change it slightly:

$name = preg_replace('~[^\p{L}\p{Mn}\p{Pd}\'\x{2019}\s]~u', '$1', $name);

示例:

• H4nn3 Andersen -> Hnn Andersen
• 马丁·亨里克森(Martin Henriksen)！ -> 马丁·亨里克森

• H4nn3 Andersen -> Hnn Andersen
• Martin Henriksen! -> Martin Henriksen

请注意，您始终需要使用 u 修饰符.

Note that you always need to use the u modifier.

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