如何检查PHP中两个字符串的部分相似性 [英] How to check a partial similarity of two strings in PHP
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问题描述
PHP中是否有任何函数检查两个字符串的相似性百分比?
Is it any function in PHP that check the % of similarity of two strings?
例如,我有:
$string1="Hello how are you doing"
$string2= " hi, how are you"
和function($string1, $string2)
将使我返回true,因为该行中出现了单词"how","are","you".
and the function($string1, $string2)
will return me true because the words "how", "are", "you" are present in the line.
甚至更好,请给我60%的相似度,因为如何",是",您"是$string1
的3/5.
Or even better, return me 60% of similarity because "how", "are", "you" is a 3/5 of $string1
.
PHP中是否存在执行该功能的函数?
Does any function exist in PHP which do that?
推荐答案
由于这是一个很好的问题,我为此付出了一些努力:
As it's a nice question, I put some effort into it:
<?php
$string1="Hello how are you doing";
$string2= " hi, how are you";
echo 'Compare result: ' . compareStrings($string1, $string2) . '%';
//60%
function compareStrings($s1, $s2) {
//one is empty, so no result
if (strlen($s1)==0 || strlen($s2)==0) {
return 0;
}
//replace none alphanumeric charactors
//i left - in case its used to combine words
$s1clean = preg_replace("/[^A-Za-z0-9-]/", ' ', $s1);
$s2clean = preg_replace("/[^A-Za-z0-9-]/", ' ', $s2);
//remove double spaces
while (strpos($s1clean, " ")!==false) {
$s1clean = str_replace(" ", " ", $s1clean);
}
while (strpos($s2clean, " ")!==false) {
$s2clean = str_replace(" ", " ", $s2clean);
}
//create arrays
$ar1 = explode(" ",$s1clean);
$ar2 = explode(" ",$s2clean);
$l1 = count($ar1);
$l2 = count($ar2);
//flip the arrays if needed so ar1 is always largest.
if ($l2>$l1) {
$t = $ar2;
$ar2 = $ar1;
$ar1 = $t;
}
//flip array 2, to make the words the keys
$ar2 = array_flip($ar2);
$maxwords = max($l1, $l2);
$matches = 0;
//find matching words
foreach($ar1 as $word) {
if (array_key_exists($word, $ar2))
$matches++;
}
return ($matches / $maxwords) * 100;
}
?>
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