Ada中的按位运算 [英] Bitwise Operations in Ada

问题描述

在某处有一个教程可以说明可以使用哪些数据类型按位运算吗？我不知道为什么艾达夫人认为我不能按位或两个Standard.Integer ...

Is there a tutorial somewhere that explains on which datatypes bitwise operations can be used? I don't know why Lady Ada thinks that I cannot bitwise OR two Standard.Integer...

$ gnatmake test.adb
gcc -c test.adb
test.adb:50:77: there is no applicable operator "Or" for type "Standard.Integer"
gnatmake: "test.adb" compilation error

真的吗？我为编译器无法与/或枚举数据类型感到抱歉。我为编译器无法对Character类型执行按位运算感到抱歉。我为编译器无法以我认为是显而易见的方式从Unsigned_8转换为Character而感到抱歉。但这是不可原谅的。

Really? I excused the compiler for not being able to AND/OR enumerated data types. I excused the compiler for not being able to perform bitwise operations on Character type. I excused the compiler for not being able to convert from Unsigned_8 to Character in what I thought was the obvious way. But this is inexcusable.

推荐答案

似乎没有人想出来回答这个该死的问题：

No one seems to want to just come out and answer the damn question:

Ada不对整数类型提供逻辑（按位）运算，而是在模块化类型。这是参考手册中的部分。

Ada doesn't provide logical (bit-wise) operations on integer types, it provides them on modular types. Here's the section in the reference manual.

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