继承int的类中的按位运算 [英] Bitwise operations in class inheriting int

问题描述

我继承自int，因为我想为按位操作实现一个简单的接口。由于int的非可变性，我必须使用整数成员函数，如 int .__和__ ，...。

I've inherited from int, because I wanted to implement a simple interface for bitwise operations. Due to the non mutability of int, I have to use the integer member functions like int.__and__, ... .

class Bitset(int)
    ...
    def __setitem__(self, index, value):
        if value:
            self.__ior__(1 << int(index))
        else:
            self.__iand__(~(1 << int(index)))

在我的一个成员函数中，我想使用 | = 和& = 函数，但整数没有 __ ior __ 和 __ iand __ 成员函数。所以我的问题是如何解决这个问题？。

In one of my memberfunctions I want to use the |= and &= functions, but the integer has no __ior__ and __iand__ member functions. So my question is how can I solve this problem?.

我不想简化二进制操作，我想操纵整数的位。例如

I dont want to simplify binary operations, I'd like to manipulate the bits of an integer. E.g.

a = Bitset(0)
a[0]
>>>0
a[0] = 1
a[0]
>>>1

但是我不想重新实现每个整数运算，它仍然可以运行。如果我包装一个内部整数，我必须这样做。例如

But I didn't wan't to reimplement every integer operation, which should still work as well. If I wrap an internal integer I've got to do that. E.g

a = Bitset(0)
a += 1

仍应有效。

推荐答案

int s不是可订阅的，也不是不可变的，所以你不能编写一个有效的 __ setindex __（）方法。似乎描述基本上是一个可变的位向量类，例如这一个似乎是由Guido写的。您可以使用提供的 __ int __（）和 __ long __（）方法将其转换为整数值（尽管我不知道相信你不再需要后者了。

ints aren't subscriptable as well as being immutable, so you can't write a working __setindex__() method. It seems like what describing is basically a mutable bit-vector class, such as this one which appears to have been written by Guido. You can use the provided __int__() and __long__() methods to convert it an integer value (although I don't believe you need the latter any more).

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