CATALINA_HOME环境变量未正确定义 [英] CATALINA_HOME environmental variable is not defined correctly
问题描述
我将Apache Tomcat 6.0安装到 C:/ Program Files
文件夹,并设置环境变量 JAVA_HOME
和 CATALINA_HOME
,但是当我使用 startup.bat
启动服务器时,出现错误:
CATALINA_HOME环境变量未正确定义。
我的 CATALINA_HOME
环境变量设置为 CATALINA_HOME = C:\Program Files\apache-tomcat-6.0.35
。 / p>
我做错了什么?
首先,您必须提及tomcat,直到tomcat的版本,请参见以下
CATALINA_HOME:C:\Program Files\apache-tomcat-6.0.35;
然后将CLASSPATH变量设置为
CLASSPATH:C:\Program Files\apache-tomcat-6.0.35\lib;
然后最后将路径变量编辑为
PATH:。;%CATALINA_HOME%\bin;
注意:必须在每个变量的末尾添加分号(;)。
I installed Apache Tomcat 6.0 to a C:/Program Files
folder and I set the environmental variables JAVA_HOME
and CATALINA_HOME
, but when I start the server using startup.bat
, I am getting the error:
CATALINA_HOME environmental variable is not defined correctly.
My CATALINA_HOME
environment variable is set to CATALINA_HOME=C:\Program Files\apache-tomcat-6.0.35
.
What did I do wrong?
At first you have to mention tomcat up to tomcat's version refer below
CATALINA_HOME: C:\Program Files\apache-tomcat-6.0.35; then set CLASSPATH variable to
CLASSPATH : C:\Program Files\apache-tomcat-6.0.35\lib;
then finally edit path variable to PATH: .;%CATALINA_HOME%\bin;
NOTE: a semicolon(;) must be put at the end of each and every variable.
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