启动tomcat时jre_home环境变量定义不正确 [英] jre_home environment variable is not defined correctly while starting tomcat

问题描述

当我尝试使用 startup.bat 运行 tomcat 时，出现以下错误，

When I am trying to run tomcat using startup.bat I get the following error,

The JRE_HOME environment variable is not defined correctly
This environment variable is needed to run this program

我什至尝试将 JRE_HOME 手动设置为系统变量列表，但此问题仍然存在.

I have even tried setting JRE_HOME manually to system variable list, but this issue remains.

我的JRE_HOME C:\Program Files\Java\jre1.8.0_121;

我能做些什么来解决它?

What can I do to solve it?

我使用的是 Windows 8

I am using Windows 8

推荐答案

希望你知道在 Windows 8 中设置路径的方式.//C:\Program Files\Java\jre1.8.0_121 肯定是因为 Program 和 Files 之间有空格，所以这种错误是可能的.请更正此路径或将其存储在不涉及空间的路径中.在 Path 添加 JRE_HOME 路径并单击确定重新打开命令提示符窗口，然后再次提供startup.bat

Hope you know the way of setting path in Windows 8. //C:\Program Files\Java\jre1.8.0_121 surely as there is space between Program and Files, these kind of errors are possible. Please correct this path or store this in a path where no space is involved. In Path add JRE_HOME path and click ok Reopen Command prompt window, then again give startup.bat

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