Python模糊匹配列表性能中的字符串 [英] Python Fuzzy matching strings in list performance
问题描述
我正在检查在4个相同的数据框列中是否有相似的结果(模糊匹配),并且以下面的代码为例.当我将其应用于实际的40.000行x 4列数据集时,将始终以整数运行.问题是代码太慢.例如,如果我将数据集限制为10个用户,则需要8分钟来计算,而要花20到19分钟.有什么我想念的吗?我不知道为什么要花这么长时间.我希望能在2小时或更短时间内获得所有结果.任何提示或帮助将不胜感激.
I'm checking if there are similar results (fuzzy match) in 4 same dataframe columns, and I have the following code, as an example. When I apply it to the real 40.000 rows x 4 columns dataset, keeps running in eternum. The issue is that the code is too slow. For example, if I limite the dataset to 10 users, it takes 8 minutes to compute, while for 20, 19 minutes. Is there anything I am missing? I do not know why this take that long. I expect to have all results, maximum in 2 hours or less. Any hint or help would be greatly appreciated.
from fuzzywuzzy import process
dataframecolumn = ["apple","tb"]
compare = ["adfad","apple","asple","tab"]
Ratios = [process.extract(x,compare) for x in dataframecolumn]
result = list()
for ratio in Ratios:
for match in ratio:
if match[1] != 100:
result.append(match)
break
print (result)
输出: [('asple',80),('tab',80)]
Output: [('asple', 80), ('tab', 80)]
推荐答案
通过编写矢量化操作并避免循环来显着提高速度
Major speed improvements come by writing vectorized operations and avoiding loops
导入必要的程序包
from fuzzywuzzy import fuzz
import pandas as pd
import numpy as np
从第一个列表创建数据框
dataframecolumn = pd.DataFrame(["apple","tb"])
dataframecolumn.columns = ['Match']
从第二个列表创建数据框
compare = pd.DataFrame(["adfad","apple","asple","tab"])
compare.columns = ['compare']
合并-引入键(自连接)的笛卡尔积
dataframecolumn['Key'] = 1
compare['Key'] = 1
combined_dataframe = dataframecolumn.merge(compare,on="Key",how="left")
combined_dataframe = combined_dataframe[~(combined_dataframe.Match==combined_dataframe.compare)]
向量化
def partial_match(x,y):
return(fuzz.ratio(x,y))
partial_match_vector = np.vectorize(partial_match)
使用矢量化并通过在分数上设置阈值来获得期望的结果
combined_dataframe['score']=partial_match_vector(combined_dataframe['Match'],combined_dataframe['compare'])
combined_dataframe = combined_dataframe[combined_dataframe.score>=80]
结果
+--------+-----+--------+------+
| Match | Key | compare | score
+--------+-----+--------+------+
| apple | 1 | asple | 80
| tb | 1 | tab | 80
+--------+-----+--------+------+
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