将MemberInitExpression分配给属性的ExpressionTree方法 [英] ExpressionTree method to Assign MemberInitExpression to property
问题描述
我正在尝试使用表达式树,以便我可以选择使用实体框架映射到DTO,方法与Include指令在DbSet上起作用的方式相同(属于实现OData的开放式源代码项目的一部分).
I am trying to use expression trees so that I can choose to map across to a DTO using entity framework in much the same way as the Include directive works on a DbSet (part of an open sorce project implementing OData).
下面的代码代表一个测试案例.
The code below represents a test case.
Expression<Func<Bar, Bar>> mapBar = b => new Bar { BarInt = b.BarInt, BarString = b.BarString };
Expression<Func<Foo, Foo>> mapFoo = f => new Foo { FooInt = f.FooInt, B = null };
Expression<Func<Foo, Foo>> target = f => new Foo { FooInt = f.FooInt,
B = new Bar {
BarInt=f.B.BarInt, BarString = f.B.BarString
} };
请注意Foo.B为空,并插入了mapBar表达式.
note Foo.B was null, and has the mapBar expression inserted.
我可以使用以下ExpressionVisitor添加导航属性
I have got as far as adding the navigation property using the following ExpressionVisitor
public class UpdateExpressionVisitor : ExpressionVisitor
{
private readonly ParameterExpression _oldExpr;
private readonly Expression _newExpr;
public UpdateExpressionVisitor(ParameterExpression oldExpr, Expression newExpr)
{
_oldExpr = oldExpr;
_newExpr = newExpr;
}
protected override MemberAssignment VisitMemberAssignment(MemberAssignment node)
{
if (node.Member.Name == _oldExpr.Name)
{
return node.Update(_newExpr);
}
Console.WriteLine(node);
return base.VisitMemberAssignment(node);
}
}
但是我不知道如何更改表达式new Bar { BarInt = b.BarInt,...
成为new Bar { BarInt = f.B.BarInt,...
But I cant figure out how to alter the expression new Bar { BarInt = b.BarInt,...
, to become new Bar { BarInt = f.B.BarInt,...
该函数将需要像这样的ExpressionVisitor
The function will need some kind of ExpressionVisitor like so
public class MergingVisitor : ExpressionVisitor
{
private readonly ParameterExpression _oldExpr;
private readonly ParameterExpression _newProp;
private readonly ParameterExpression _newParent;
public MergingVisitor(ParameterExpression oldExpr, ParameterExpression newProp, ParameterExpression newParent)
{
_oldExpr = oldExpr;
_newProp = newProp;
_newParent = newParent;
}
protected override Expression VisitMember(MemberExpression node)
{
if (node.Expression == _oldExpr)
{
/*!!what to do here!!*/
var ma = Expression.MakeMemberAccess(_newProp, node.Member);
return Expression.MakeMemberAccess(_newParent, ma.Member);
}
return base.VisitMember(node);
}
它们都需要与类似的东西链接在一起
and they all need to be linked together with something like
public static Expression<Func<T, TMap>> MapNavProperty<T, TMap, U, UMap>(this Expression<Func<T, TMap>> parent, Expression<Func<U, UMap>> nav, string propName)
{
//concern 1 remap name of prop in nav - not sure if I should do this first
var parentInitVarName = parent.Parameters[0].Name;
var parentParam = Expression.Parameter(typeof(T), parentInitVarName);
var propParam = Expression.Parameter(typeof(U), propName);
var mergeVisitor = new MergingVisitor(nav.Parameters[0], propParam, parentParam);
var newNavBody = mergeVisitor.Visit(nav.Body); //as MemberExpression;
//concern 2 replace given property
var visitor = new UpdateExpressionVisitor(propParam, nav.Body);
return (Expression<Func<T, TMap>>)visitor.Visit(parent);
}
尽管目前,parentParam将在Expression.MakeMemberAccess
函数中失败,因为它的类型为T(在上面的示例中为Foo),而不是类型U.
although at present the parentParam will fail in the Expression.MakeMemberAccess
function as it is of type T (Foo in the above example), rather than type U.
如何更改子属性的lamda表达式中的变量名称和类型-谢谢.
How can I alter the variable name and types in the child property's lamda expression - thank you.
Svick和Ivan Stoev的答案在解释上很博学,并且都很好用-两个答案的(通过的)单元测试和代码都已建立
The answers from Svick and Ivan Stoev are erudite in explanation and both work perfectly - the (passing) unit tests and code from both answers are up on GitHub here. Thank you so much to both of you - it is a shame I cannot tick 2 answers, so it comes down to Eeny, meeny, miny, moe.
推荐答案
var parentParam = Expression.Parameter(typeof(T), parentInitVarName);
这不起作用,表达式中的参数不是通过名称标识的,而是通过引用标识的.您需要做的就是获取父母的参数.
This won't work, parameters in expressions are not identified by name, but by reference. What you need to do is just get the parent's parameter.
var propParam = Expression.Parameter(typeof(U), propName);
这对我来说没有任何意义. propName
是属性的名称,因此您需要使用它来创建成员访问表达式,而不是参数表达式.
This doesn't make any sense to me. propName
is the name of a property, so you need to use it to create member access expression, not parameter expression.
public MergingVisitor(ParameterExpression oldExpr, ParameterExpression newProp, ParameterExpression newParent)
您需要的是用另一个表达式(f.B
)替换一个表达式(b
).为此,我将创建:
What you need is to replace one expression (b
) with another (f.B
). For that, I would create:
public class ReplaceVisitor : ExpressionVisitor
{
private readonly Expression _oldExpr;
private readonly Expression _newExpr;
public ReplaceVisitor(Expression oldExpr, Expression newExpr)
{
_oldExpr = oldExpr;
_newExpr = newExpr;
}
public override Expression Visit(Expression node)
{
if (node == _oldExpr)
{
return _newExpr;
}
return base.Visit(node);
}
}
public UpdateExpressionVisitor(ParameterExpression oldExpr, Expression newExpr)
oldExpr
作为参数表达式没有任何意义.您只需要一个string
.
It doesn't make any sense for oldExpr
to be a parameter expression. What you need is just a string
.
var visitor = new UpdateExpressionVisitor(propParam, nav.Body);
您需要在此处实际使用newNavBody
.
You need to actually use newNavBody
here.
整个MapNavProperty()
现在看起来像这样:
The whole MapNavProperty()
will now look like this:
var parentParam = parent.Parameters.Single();
var propExpression = Expression.Property(parentParam, propName);
var mergeVisitor = new ReplaceVisitor(nav.Parameters.Single(), propExpression);
var newNavBody = mergeVisitor.Visit(nav.Body);
var visitor = new UpdateExpressionVisitor(propName, newNavBody);
return (Expression<Func<T, TMap>>)visitor.Visit(parent);
通过这些更改,您的代码将可用.
With these changes, your code will work.
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