python getattr内置方法执行默认参数 [英] python getattr built-in method executes default arguments
问题描述
我不知道这是否是getattr
Built_in方法的预期行为.
即使实际参数(2nd)满足条件,getattr
也会执行default(3rd)参数.
示例:
I dont know if this is something an expected behavior of getattr
built_in method.
getattr
executes the default(3rd) argument as well even if the actual argument(2nd) satisfies the condition.
Example:
def func():
print('In Function')
class A:
def __init__(self):
self.param = 12
a = A()
当我运行getattr(a, 'param', func())
时,它会给出以下结果:
When I run getattr(a, 'param', func())
it gives this result:
In Function
12
注意我不想要的In Function
.
但是当我执行getattr(a, 'param1', func())
即输出时,它工作得很好
But it works perfectly fine when I execute getattr(a, 'param1', func())
i.e output
In Function
但是如果满足条件,我只希望结果为12
.请让我知道为什么getattr
具有这种行为,我们能否阻止他们这样做(如果有第二个参数,则不执行第3个arg),如果以Pythonic方式共享它的另一种选择,将不胜感激.
首先想到的一件事是使用hasattr
检查param1
是否存在,然后做有需要的事情.
But I only want result as 12
if satisfied the condition. Please let me know why getattr
has such behaviour and can we stop them of doing it (that is not to execute 3rd arg if has 2nd argument), would be appreciated if share the alternate way of doing it in Pythonic way.
One thing that comes in mind first is to check if param1
exist using hasattr
and then do the needful.
推荐答案
在执行getattr
之前,必须评估所有传递的参数. func()
是这些参数之一,尝试对其进行评估将执行print
语句.无论是否找到该属性,必须先对func()
进行评估.
Before getattr
gets executed, all the passed parameters have to be evaluated. func()
is one of those parameters and an attempt to evaluate it will execute the print
statement. Whether the attribute will be found or not, func()
must be evaluated apriori.
这不是getattr
所特有的,这是函数及其参数在Python中的工作方式.
This isn't peculiar to getattr
, it's how functions and their parameters work in Python.
请考虑以下内容:
>>> def does_nothing(any_arg): pass
...
>>> def f(): print("I'll get printed")
...
>>>
>>> does_nothing(f())
I'll get printed
函数does_nothing
实际上对传递的参数不执行任何操作.但是必须在函数调用通过之前对参数进行求值.
Function does_nothing
actually does nothing with the passed parameter. But the parameter has to be evaluated before the function call can go through.
print
语句不会影响getattr
的结果;一种副作用.如果找不到该属性,则使用该函数的return
值.
The print
statement however will not affect the outcome of getattr
; sort of a side effect. In the event the attribute is not found the return
value of the function is used.
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