获取内置方法签名 - Python [英] Get built in method signature - Python

问题描述

如何获取内置方法的签名?示例:dict().get(k)

How do I get the signature of built in methods? Example: dict().get(k)

>> a = dict().get
>> a
<built-in method get of dict object at 0x1003aafd0>
>> a.__doc__
'D.get(k[,d]) -> D[k] if k in D, else d.  d defaults to None.'
>> import inspect
>> inspect.getargspec(a)
TypeError: <built-in method get of dict object at 0x100377250> is not a Python function

我想看到这样的结果

>> a.some_function()
('key', 'default'=None)

推荐答案

我不认为这对于用 C 实现的 Python 中的内置函数是可能的.参见 this 错误讨论以获取更多详细信息.

I don't think this is possible for the built-in functions in python that are implemented in C. See this bug discussion for further details.

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