构建完成后退出gulp [英] exit gulp when build is finished

问题描述

我正在使用gulp来缩小CSS和JS文件.

I'm using gulp to minify CSS and JS files.

当我从终端运行gulp命令gulp build:website1:desktop时，它成功完成，但没有返回到shell提示符，我必须运行Ctrl+C以返回到命令提示符

When I run the gulp command gulp build:website1:desktop from a terminal, it finishes successfully but it does not return to the shell prompt, I have to run Ctrl+C to return to the command prompt

这是我正在使用的

gulp.task('build:website1:desktop', function () {
runSequence(
    'website1:desktop:scripts',
    'website1:desktop:css');
  })

任何想法如何在不每次都键入Ctrl+C的情况下退出并返回命令提示符?

Any ideas How to exit and return to the command prompt without typing Ctrl+C every time?

谢谢.

推荐答案

第一件事是确保您的scripts和css任务返回流或诺言，以便runSequence知道何时执行这些任务完成的.对于大多数gulp任务，将return语句与gulp.src(…)一起使用即可做到:

First thing is to make sure that your scripts and css tasks return a stream or a promise, so that runSequence knows when these tasks are finished. For most gulp tasks, using the return statement with gulp.src(…) will do just that:

gulp.task('website1:desktop:scripts', function() {
  return gulp.src(…)
    .pipe(doSomething())
    .pipe(gulp.dest(…));
});

接下来的事情是为runSequence提供回调:

Next thing is to provide a callback for runSequence:

gulp.task('build:website1:desktop', function (callback) {
  runSequence(
    'website1:desktop:scripts',
    'website1:desktop:css',
    callback);
});

这应该可以解决问题.

这篇关于构建完成后退出gulp的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！