构建完成后拷贝文件到目标目录 [英] Copy files to the target directory after build

问题描述

假设我有一个具有以下目录结构的游戏:

Let's assume I have a game with the following directory structure:

/src
/resources
Cargo.toml

我希望 cargo build 将 resources 目录中的文件复制到与可执行文件相同的目录中.

I would like cargo build to copy the files in the resources directory and paste them in the same directory as the executable file.

我知道可以使用自定义构建脚本来做到这一点，但这似乎是一个值得特殊对待的常见情况.所以问题是:cargo 是否提供了将文件复制到目标目录的标准方式(仅使用 Cargo.toml)?

I know it is possible to do this using a custom build script, but this seems to be a common case that deserves special treatment. So the question is: does cargo provide a standard way of copying files to the target directory (using just Cargo.toml)?

推荐答案

不，没有.

您可以使用 构建脚本 移动文件，但这些在您的 crate 之前运行之所以构建，是因为它们的唯一目的是准备环境(例如编译 C 库和垫片).

You can move files around with build scripts, but these are run before your crate is built because their sole purpose is to prepare the environment (e.g. compile C libraries and shims).

如果你认为这是一个重要的特性，你可以在 Cargo issue tracker/a>.

If you think this is an important feature, you can open a feature request in Cargo issue tracker.

或者，您可以编写一个 makefile 或 shell 脚本，将所有参数转发给货物，然后手动复制目录:

Alternatively, you can write a makefile or a shell script which would forward all arguments to cargo and then copy the directory manually:

#!/bin/bash

DIR="$(dirname "$0")"

if cargo "$@"; then
    [ -d "$DIR/target/debug" ] && cp -r "$DIR/resources" "$DIR/target/debug/resources"
    [ -d "$DIR/target/release" ] && cp -r "$DIR/resources" "$DIR/target/release/resources"
fi

现在你可以像这样运行货物

Now you can run cargo like

% ./make.sh build

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