Python列表排序 [英] Python List Sorting

问题描述

my_list=raw_input('Please enter a list of items (separated by comma): ')
my_list=my_list.split()
my_list.sort()

print "List statistics: "

for x in my_list:
    z=my_list.count(x)

    if z>1:  
        print x, "is repeated", z, "time."
    else:
        print x, "is repeated", z, "times."

我正在尝试使该程序按字母顺序对列表进行排序，然后打印找到的每个列表的数量.输出为:

I am trying to get the program to sort the list alphabetically, then print how many of each it found. The output is:

List statistics: 
bird, is repeated 1 time.
cat, is repeated 1 time.
dog is repeated 1 time.
dog, is repeated 2 times.
dog, is repeated 2 times.

我只需要打印一次即可.另外，我试图弄清楚如何将项目放在引号中.

I only need it to print one time each. Also, I am trying to figure out how to put the item in quotation marks.

推荐答案

from itertools import Counter
my_list=raw_input('Please enter a list of items (separated by comma): ')
my_list=my_list.split(",")


print "List statistics: "
import operator
for item,count in sorted(Counter(my_list).items(),key =operator.itemgetter(0)) :

    if z==1:  
        print  '"%s" is repeated %d time.'%(item,count)
    else:
        print  '"%s" is repeated %d times.'%(item,count)

如果您使用的是python< 2.7您可以创建自己的计数器方法

if you are using python < 2.7 you can make your own counter method

def Counter(a_list):
    d = {}
    for item in a_list:
        if d.get(item,None) is None:
           d[item] = 0
        d[item] += 1
    return d

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