为什么内联声明不是不完整的类型? [英] Why an inline declaration is not an incomplete type?
问题描述
考虑以下代码:
struct Foo {
struct Bar;
Foo()
{
Bar bar; // Why isn't Bar an incomplete type?!
}
struct Bar {}; // Full definition
};
// struct Bar {}; // fails to compile due to incomplete type
int main()
{
Foo foo;
}
它至少可以在2个编译器(gcc5.2,clang3.5)下编译良好.我的问题是:
It compiles fine under at least 2 compilers (gcc5.2, clang3.5). My question is:
- 为什么在构造函数
Foo::Foo
中不认为Bar
是不完整的类型,因为我在构造函数上方进行了前向声明,但在构造函数内部充分使用了它?
- Why isn't
Bar
considered an incomplete type in the constructorFoo::Foo
, as I forward-declare it above the constructor but fully use it inside the constructor?
每当我将Foo::Bar
移到班级之外,换句话说Bar
成为独立的班级,我就会得到预期的
Whenever I move Foo::Bar
outside the class, in other words Bar
becomes a stand-alone class, I get the expected
错误:聚集的'Foo :: Bar bar'类型不完整,无法定义
error: aggregate 'Foo::Bar bar' has incomplete type and cannot be defined
推荐答案
在成员规范中,该类被认为是功能体内完整的类,摘自C ++标准草案9.2
[class.mem] :
Within the member specification the class is considered complete within function bodies, from the draft C++ standard section 9.2
[class.mem]:
一个类被认为是完全定义的对象类型(3.9)(或 完整类型)在class-specifier的结尾}处. 在 类成员的规范,该类被认为是完整的 函数体,默认参数,使用声明介绍 继承构造函数(12.9),异常规范和 非静态数据成员(包括 嵌套类中的此类内容).否则被认为是不完整的 在自己的类成员规范内
A class is considered a completely-defined object type (3.9) (or complete type) at the closing } of the class-specifier. Within the class member-specification, the class is regarded as complete within function bodies, default arguments, using-declarations introducing inheriting constructors (12.9), exception-specifications, and brace-or-equal-initializers for non-static data members (including such things in nested classes). Otherwise it is regarded as incomplete within its own class member-specification
这意味着您甚至不必转发声明Bar
( 实时查看 ):
Which means you don't even have to forward declare Bar
(see it live):
struct Foo {
Foo()
{
Bar bar;
}
struct Bar {};
};
前瞻性声明对于避免违反 3.3.7第2和第3 节可能很有用.
Forward declaring could be useful in avoiding violation of section 3.3.7 paragraph 2 and 3.
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