我怎样才能从（X，Y）位置的ListView项？ [英] How can I get an ListView item from the (X,Y) position?

问题描述

我在WPF一个ListView下降东西。我需要知道我丢弃（X，Y）的位置的项目。我怎样才能做到这一点？

I am dropping something in a ListView in WPF. I need to know the item in the (X,Y) position I am dropping. How can I do this?

在WPF ListView控件没有话getItemAt。我回到我原来的问题。

The WPF ListView doesn't have GetItemAt. I return to my original problem.

推荐答案

完成！由于这篇文章
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private int GetCurrentIndex(GetPositionDelegate getPosition)
{
    int index = -1;
    for (int i = 0; i < clasesListView.Items.Count; ++i)
    {
        ListViewItem item = GetListViewItem(i);
        if (this.IsMouseOverTarget(item, getPosition))
        {
            index = i;
            break;
        }
    }
    return index;
}

private bool IsMouseOverTarget(Visual target, GetPositionDelegate getPosition)
{
    Rect bounds = VisualTreeHelper.GetDescendantBounds(target);
    Point mousePos = getPosition((IInputElement)target);
    return bounds.Contains(mousePos);
}

delegate Point GetPositionDelegate(IInputElement element);

ListViewItem GetListViewItem(int index)
{
    if (clasesListView.ItemContainerGenerator.Status != GeneratorStatus.ContainersGenerated)
        return null;

    return clasesListView.ItemContainerGenerator.ContainerFromIndex(index) as ListViewItem;
}

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